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Forum Index : Windmills : Windmill thrust loading
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rber![]() Newbie ![]() Joined: 26/04/2008 Location: CanadaPosts: 4 |
Hi Guys Knee deep in the planning stages of my mill project. Just wondering if anyone has any idea of what kind of thrust an ~ 3m, 3 blade, single f&p alternator unit would present to a free standing tower of 60 ft @ say, 70 mph wind or perhaps some good online resources dealing with wind turbine wind loading. Thanks in advance. Ray |
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hoodlem![]() Newbie ![]() Joined: 02/07/2008 Location: AustraliaPosts: 7 |
I take it that the blades are 1.5 metre long so the sweep area would be about seven square metres and I read somewhere that a wind turbine has the same wind resistance as a solid disc sitting on top of the tower. So talk to some people who put sign's up for a living and ask them about wind loading free information for all |
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Gill![]() Senior Member ![]() Joined: 11/11/2006 Location: AustraliaPosts: 669 |
G'day rber, The thrust can be calculated by the formula used in the calculations for furling found on this site. Here But in essence it says: Turbine Thrust = Diameter2 * WindSpeed2 / 24 Turbine Thrust = 2m2 * 20m2 / 24 = 66.6kg This is one of the many formula available on numerous sites. The true loading is somewhat less but structural engineers prefer it that way so their towers don't fall down. Hope that helps. ![]() was working fine... til the smoke got out. Cheers Gill _Cairns, FNQ |
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rber![]() Newbie ![]() Joined: 26/04/2008 Location: CanadaPosts: 4 |
Thanks Gill. I'll get my calculator out and start crunching. ![]() |
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