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I was sitting down with the calculator and ended up confused.
In Star - at any instant I would have 10 coils in series. These coils have 50 turns of .55 mm square wire x 2 strands with a resistance of .15 Ohms. 10 Coils x .15 Ohms = 1.5 Ohms
In Delta - at the same instant I could have 5 coils of 100 turns of .55 mm square wire(to increase voltage)Each of these coils has resistance of .3 Ohms. 5 x .3 Ohms = 1.5 Ohms. But there is a second path through the other two phases.
So the total reistance is the reciprical of 1.5 Ohms + 3 Ohms.
So if the maths are correct (1/1.5) + (1/3) = 1/r total which in this case is 1 Ohm. Near as dammit.
Does this mean the overall resistance at an instant is lower in Delta even though the coils have twice the resistance?
Do I understand this correctly, would I need to increase my windings by the value of root 3 (1.73 ish)to get the same voltage from delta as star?